Deriving Einstein’s Greatest Equation
E = mc^2
Stationary box A is floating in Space.
A Photon is then emitted from the left and moves towards the right.
E=Energy of the photon
Momentum(p) of a Photon=E/c
The box experiences a recoil force and moves towards the left with a velocity v.
p of box=Mv
Where M = mass of the box
By Conservation of momentum,
M∆x/∆t=E/c - 1
Where ∆x is the distance the box moves in time ∆t when the photon makes it to the other side.
∆t=L/c
Where L = the length of the box
Substituting this in 1,
M∆x=EL/c^2
Assuming the photon has mass m, if the box has a position x1 and the photon has a position x2, the centre of mass for the whole system is,
=(Mx1+mx2)/(M+m)
Since no external force was applied, the centre of mass of the whole system should not change.
Therefore,
(Mx1+mx2)/(M+m)=(M(x1-∆x)+mL)/(M+m)
The photon starts at the left of the box.
Thus x2 + 0
Hence,
mL=M∆x
mL=EL/(c^2)
m=E/c^2
Or,
E=mc^2
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