This blog is dedicated to Science, mostly physics and chemistry, and is the facts presented in the blog are true o the best of my knowledge (though that might just be next to nothing).
Note: For best results plz read from the bottom-up.....
A fighter plane is flying in a straight line on a level course to cross the course of a bomber which is also flying on a level course in a straight line. The fighter is at a level 500 meters above the bomber, and their courses cross at an angle of 60 degrees. Both planes are headed toward the crossing at 300 and 200 km/h respectively. At the moment when the fighter is 10km and the bomber 7 km from the crossing point, how rapidly are they approaching one another in a straight line joining the 2 planes?
(taken from the book "calculus for the practical man")
Sci Savvy...
For the Relativity savvy:
The formula to calculate the rate of passage of time for a body moving with velocity v is:
t1 = t0/sqrt. (1 - v^2/c^2)
where,
*t1 is the rate of passage of time for the body/observer at velocity v
*t2 is the rate of passage of time for a stationary observer
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